Question

A large fish tank is filled with water. The pressure on the base of the fish tank 4000N/m. The base of the tank is a rectangle measuring 2.0 n by 4.5 m. A) calculate the area of the base. B) calculate the force on the base caused by the pressure of the water

Answer 1

Given:

The pressure on the base of the fish tank 4000N/m.

The base of the tank is a rectangle measuring 2.0 m by 4.5 m.

To find:

A) calculate the area of the base.

B) calculate the force on the base caused by the pressure of the water.

Explanation:

The pressure on the base of the fish tank is 4000N/m².

The base of the tank is a rectangle measuring 2.0 m by 4.5m.

Area of the base of the tank is   = ( Length × Breadth)

                                                    = (4.5 ×2)

                                                     = 9 m².

∴ The are of the base of the  tank is 9 m².

We need to find the force on the base caused by the base of the water. Pressure on the base of the tank is given by the force acting per unit area such that,

P = $\frac{F}{A}$

⇒ F = ( P×A)

⇒ F = (4000×9)

⇒ F = 36000 N

⇒ F = 36 KN

So, the force of 36 KN is acting on the base by the base of water tank.

Answer:

              (A) The are of the base of the  tank is 9 m².

              (B) The force of 36 KN is acting on the base by the base of water                 tank.

Answer 2

Given:

A large fish tank is filled with water. The pressure on the base of the fish tank 4000N/m. The base of the tank is a rectangle measuring 2.0 m by 4.5 m

To find:

• Area of base ?
• Force of water at base ?

Calculation:

• Area of rectangular base

$= 2 \: m \times 4.5 \: m$

$= 9 \: {m}^{2}$

• Now, force at base will be pressure multiplied with the area of base:

$F = P \times area$

$\implies \:F = 4000 \times 9$

$\implies \:F = 36000 \: N$

$\implies \:F = 36 \: kN$

So, area of base is 9 m² and force at base is 36 kN.