A large He balloon of volume 1425 m³ is used to lift a payload of 400 kg. Assume that the balloon maintains constant radius as it rises. How high does it rise ?
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your question is incomplete. A complete question is ----> A large He balloon of volume 1425 m³ is used to lift a payload of 400 kg. Assume that the balloon maintains constant radius as it rises. How high does it rise ?(
=8000m,
)
Volume of He balloon, V = 1425 m³
mass is used to lift a payload , m = 400kg
total mass of balloon , M =
M = 400 kg + 1425 × 0.18
M = 400kg + 256.5 kg
M = 656.5 kg
so, density ,
= 656.5/1425
= 0.46 kg/m³
we know, rate of change of decreases of density per unit height from the sea level is directly proportional to density
e.g.,



put k = 1/y0

now, put the values of all given data.
so, y = 8000 m = 8km
Volume of He balloon, V = 1425 m³
mass is used to lift a payload , m = 400kg
total mass of balloon , M =
M = 400 kg + 1425 × 0.18
M = 400kg + 256.5 kg
M = 656.5 kg
so, density ,
= 656.5/1425
= 0.46 kg/m³
we know, rate of change of decreases of density per unit height from the sea level is directly proportional to density
e.g.,
put k = 1/y0
now, put the values of all given data.
so, y = 8000 m = 8km
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