Question

a large number of balls vertically upwards in quick succession @ 30 balls per minute he throws the balls in such a way that each ball is thrown after the previous ball reaches its maximum height the maximum height reached by each ball is

Answer 1

Answer:

time of throw between two balls= 60/30= 2 s

so as per question every ball takes 2s to reach maximum height

so as V = u + at

0 = u + (-10) ×2

u = 20 m/s

now

s=ut +1/2 a t^2

=20×2+1/2(-10) ×2×2= 20m

Answer 2

ans : 20m, 20m, 20m, 20m, 20m.