A large number of bullets are fire in all direction with same speed v .what is the maximum area on the ground on which this bullet will spread
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Answered by
24
Hey User
For maximum area to be covered radius/range must be maximum
For maximum range(R) ∅ = 45°
so, R = v²sin(2∅)/g
= v²/g
hence area covered = πR²
i.e. π(v²/g)² = π×v⁴/g²
like if You understood
For maximum area to be covered radius/range must be maximum
For maximum range(R) ∅ = 45°
so, R = v²sin(2∅)/g
= v²/g
hence area covered = πR²
i.e. π(v²/g)² = π×v⁴/g²
like if You understood
Answered by
1
Answer:
(pi v^(4))/(g^(2))`
Explanation:
The bullets will spread in a circle. The area will be maximum,
when `theta = 45^(@)`
Radius of circle:
`r = R_(max) = (u^(2))/(g)`
Area of circle `= pi r^(2) = (pi v^(4))/(g^(2))`
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