A large number of bullets are fired in all directions with same speed u. The maximum area on the ground covered by these bullets will be
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Pie×r² where r is distance 0° from horizontal
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Given :-
Speed of bullets = u m/s
As we know that bullets will move in Projectile.
Area covered = πr²
For Maximum Area,
r = R(max) = u²/g (When Ø = 45° then R is max).
Maximum Area = πr²
M. A. = π (u²/g)²
M.A. = πu⁴/g²
Hence,
Maximum Area covered = πu⁴/g².
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