Question

A large piece of the cork floats on water with 4/5th of its volume above the water surface. Calculate the density of the cork, if the density of water is 1000 kg/m3

Answer 1

Answer:

Density of cork = 0.00002 g/cm³.

Explanation:

Given,

Volume of cork = 4/5

Density of water = 1000 kg/m³

Solution,

Let volume of cork be 'V' and density 'd'.

Volume of cork immense =

$= V - \frac{4}{5} \\ V = \frac{1}{5} V$

By principle of flotation,

Weight of cork = Weight of water displaced

$= V \times d \times g = \frac{1}{5} \times V \times 1 \times g \\ = d = \frac{1}{5} = 0.02 \: gcm ^{3}$

By taking the density of water,

$= \frac{0.02}{1000} = 0.00002 \: gcm^{3}$

Density of cork = 0.00002 g/cm³.