Question

a large rectangle as a length of 60 metres and width of 20 metres a smaller rectangle has a length of 30 metres and width of 20 metres find the perimeter of both rectangles and find the relationship of perimeters​

Answer 1

Step-by-step explanation:

perimeter of large rectangle = 2 (L+b)

=2 (60+20)

= 2×80

= 160 m

perimeter of small rectangle =2 (L+b)

= 2 (30+20)

= 3×50

, = 100 m

total perimeter = 160 m+ 100 m

=260m

Answer 2

Answer:

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