A large right circular cone is made out of solid cube of edge 9cm find volume of remaining solid
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just use photomath or papamath
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Height of cone would be equal to edge of cube (h) = 9 cm
Diameter of circular base of cone is equal to edge of cube = 9 cm
Radius (r) = d/2 = 4.5 cm
Edge of cube (a) = 9 cm
Volume of remaining solid = Volume of cube - Volume of cone
Volume of remaining solid = 729 - 190.85 = 538.15 cubic cm
Thus, Volume of remaining solid would be
ruchibbhatnagar:
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