Question

A large sheet of surface area 300 m2 has a charge of 1800 μC distributed uniformly on its surface. Find the electric field at a distance of 15 cm from it.

Answer 1

Given ,

The area of plane sheet = 300 m²

The charge on a sheet (q) = 1800 uC

We know that ,

The amount of charge present in a given area is called surface charge density

$\large \mathtt{\fbox{Surface \: charge \: density \: (σ )= \frac{q}{s} }}$

Thus ,

σ = 1800 × (10)-6/300

σ = (18/3) × (10)-6

σ = 6 × (10)^-6 C•m²

We know that ,

The electric field due to a uniformly charged large sheet is given by

$\large \mathtt{\fbox{E = \frac{ σ}{2 e_{o}}} }$

Thus ,

$\sf \hookrightarrow E = \frac{6 \times {(10)}^{ - 6} }{2 \times 8.85 \times {(10)}^{ - 12} } \\ \\ \sf \hookrightarrow E = \frac{3 \times {(10)}^{6} }{8.85} \\ \\\sf \hookrightarrow E = 3.3 \times {(10)}^{5} \: \: n/c \: \: or \: \: v/m$

Hence , the electric field is 3.3 × (10)^5 n/c or v/m

Answer 2

$\large \underline{ \red{ \boxed{ \bf \pink{Question}}}}$

A large sheet of surface area 300 m2 has a charge of 1800 μC distributed uniformly on its surface. Find the electric field at a distance of 15 cm from it.

$\large \underline{ \red{ \boxed{ \bf \pink{Answer}}}}$

$3.3 \times {10}^{5} v {m}^{ - 1}$