Question

A large tank begins to leak at the rate of 25 litres per hour. the amount of water escaping is 25 litres more than each hour than the previous hour , till the leak remain undetected. when the leak was eventually discovered , the rate of leakage was 900 litres per hour. for how long had the tank been leaking? what was total amount of water lost between the beginning of the leakage and the time of discovery?​

Answer 1

Given

a = 25

d = 25

l = 900

So AP is 25,50,75,......900

l = a+(n-1)d

900 = 25+(n-1).25

875/25 = n-1

35 = n-1

n = 36

S = n/2[a+l]

S = 36/3[25+900]

S = 12×925

S = 11100

So the tank had been leaking for 36 hours and total amount of water lost is 11100 litres.