Question

. A large tanker can be filled by two pipes A and B in 60 minutes and 40 minutes
respectively. How many minutes will it take to fill the tanker from empty
state if B is used for half the time and A and B fill it together for the other
half?
(D.M.R.C. 2003)
(1) 20 minutog.
fo) 275 minutes
(0) 30 minutes​

Answer 1

Answer:

Suppose it takes 2x minutes to fill up the whole tanker.

According to the problem, B will fill for half the time. i.e., for x minutes. Since B fills up the tanker in 40 minutes alone, it can fill up 1/40 of the tanker in 1 minutes. B will, therefore, fill x/40 of the tanker in x minutes.

Again according to the problem, A and B will work together for the remaining half time. Hence they can fill x/60 + x/40 = x/24 of the tanker in x minutes.

By this time the whole tanker is filled. Therefore, x/40 + x/24 = 1 => x = 15. But x is half the time.

Therefore given the situation, the tanker gets filled in 30 minutes.

Step-by-step explanation:

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