Question

A large urn contains 100 balls, of which 36% are red and the rest are blue. How many of the blue balls must be removed so that the percentage of red balls in the urn will be 72% (no red balls are to be removed.)

Answer 1

Answer:

Step-by-step explanation:

Now 36% are red means 36 are red and 100-36 or 64 are blue.

Some blue balls are removed and 36 has now become 72%.

Let the final number after removal is y..

So 7210072100y=36.....y=36*100/72=50

So the total number of balls left is 50, which means 100-50 or 50 have been removed.

As we know only blue balls have been removed, 50 blue balls must be removed..