Question

a large vessel is filled with water upto a height of 35 m there is a hole of radius 1 cm in the vessel wall at 7 m below the free surface of water compute [1] velocity of efflux of water [2] rate of flow of water [3] range of water flow [4] the distance below the water surface where the flow of water through a hole will have the same range as at 7m [5] the distance below the water surface where the flow of water through a hole will have maximum [6] maximum range

Answer 1

Answer:

Explanation:

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Answer 2

Answer:

Explanation:

velocity of efflux = root 2gh

=root 140

~11.6

rate of flow =av

pi*r^2*11.6

0.0036 m^3 /sec

3.6 lt/sec

range =2root h(H-h)

=2 root 7*28

=28 m

range 1= range 2

2 root h1(H-h1) = 2root h2(H-h2)

h1(H-h1)=h2(H-h2)

7(35-7) = h2(35-h2)

196=35h2-h2^2

h2^2-35h2+196=0

h2=28m and 7m

h2=28m

maximum range =H/2

=35/2

=17.5m