A large water - melon weighs 20 kg with 96% of its weight being water. It is allowed to stand in the sun and some of the water evaporates so that only 95% of its weight is water. Its reduced weight will be ?
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Answer:
1 kg
Step-by-step explanation:
Melon weight - 20 kg
Water weight - 96% of 20 kg
= 19.2 kg.
95% of water evaporated - which is 19 kg.
So only 1% of water left - which is 200 grams.
Melon weight = 20.0 - 19.2
= 800 gram.
Weight after evaporation = 800 gram ( melon weight without water ) + 200 gram ( weight of 1 % water. )
= 800+200
= 1 kg
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