A large water melon weighs 20 kg with 96% of its weight being water. It is allowed to stand in the sun and some of the water evaporates so that now only 95% of its weight is water. Its reduced will be
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Answer:
Weight of water in the 20 kg water - melon
= 96×20/100 = 19.2 kg
Weight of water - melon pulp = 20 kg – 19.2 kg
= 0.8 kg
Let the reduced weight of the water - melon be x kg. Then,
Weight of water in the water - melon after evaporation = 95%
=> Weight of pulp = 5%
Therefore, 5% of x = 0.8 kg
=> 5% of x = 0.8 kg
=> x = 16 kg.
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In 20kg 96% is water I.e 19.2 kg and rest is non water part that is 0.8 kg.
Now it dries
So water is 95% that just mean non water part is 5% and non water cant be evaporate so it remains same I.e 0.8kg
5% ---> 0.8 kg
100% --> ?
= 16 kg answer
Hope it helps you please mark me as a brainlist
Now it dries
So water is 95% that just mean non water part is 5% and non water cant be evaporate so it remains same I.e 0.8kg
5% ---> 0.8 kg
100% --> ?
= 16 kg answer
Hope it helps you please mark me as a brainlist
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