Question

A large water melon weighs 20 kg with 96% of its weight being water. It is allowed to stand in the sun and some of the water evaporates so that now only 95% of its weight is water. Its reduced will be ​

Answer 1

Answer:

$\huge\underline\bold {Answer:}$

Weight of water in the 20 kg water - melon

= 96×20/100 = 19.2 kg

Weight of water - melon pulp = 20 kg – 19.2 kg

= 0.8 kg

Let the reduced weight of the water - melon be x kg. Then,

Weight of water in the water - melon after evaporation = 95%

=> Weight of pulp = 5%

Therefore, 5% of x = 0.8 kg

=> 5% of x = 0.8 kg

=> x = 16 kg.