a large water tank begins to Leak 25 litres per hour the amount of water escaping is 25 litres more than its are than the previous are still the leak remains undetected when the Leak was eventually discovered the rate of leakage was 900 per hour for how long had the time being leaking what was the total amount of water lost between the beginning of the leakage and the time of the discovery
Answers
Answer:
35 hours water was leaking
16187.5 liters water was wasted
Step-by-step explanation:
For condition 1
v = 900 liters / hour (final velocity)
u = 25 liters / hour (initial velocity)
a = 25 liters / hour (acceleration)
t = ?
v = u+at
900 = 25 +25 * t
875 / 25 = t
35 = t
t = 35 hours the tanks had been leaking
For Condition 2
Total amount of water lost between the beginning of the leakage and time of discovery is ->
s = ut + 1/2 at2
s = 25 * 35 +1/2 *25 * 35 * 35
s = 875 + (25*17.5 *35)
s = 875 + (17.5 * 875)
s = 875 + 15312.5
s = 16187.5 liters
Answer:
Step-by-step explanation:
the water leaking is in AP with
a=25 d=25 tn=900
tn=a+(n-1)d
900=25+(n-1)25
by solving
n=36
the water is flowing for 36hrs
Sn=n/2(t1+tn)
=36/2(25+900)
18*925
=16650
the total water lost is 16650 litre