Question

A large water tank is filled at a constant rate of 10 litres/min. It has a outlet of maximum flow of 10 litres/min

at the bottom of the tank, but the output is proportional to the water present in the tank at any given

time. How will the 'v', volume of water content in the tank, change with time ? ​

Answer 1

Answer:

As we can see from graphs, initial volume in the tank is assumed to be 0.

So as the volume of liquid increases in tank its flow rate will also increase but filling rate is constant

so net rate will decrease ,

That is

dt

2

d

2

V

<0

After a long time when the volume in tank reaches to its maximum value , Flow rate = filling rate .Thus volume will become constant after a long time