A laser beam having a wavelength of 8000 Å and aperture 0.5 cm is sent to moon.
Calculate, (a) Angular spread of the beam (b) A real spread of the beam when it
reached the moon. Given distance of moon from the earth = 4 x10 8 m.
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Given:
The wavelength of the beam is 8000 A= 8×10⁻⁷ m
The aperture is 0.005 m
To find:
The angular speed and real spread of beam
Solution:
The formula of angular speed is
Ф=1.22×λ/a
Putting the above values
Ф=1.22×8×10⁻⁷/0.005
Ф=1.952×10⁻⁴ rad
Now the real spread of beam is
=(DФ)²
=(4×10⁸×1.952×10⁻⁷)
=7.808×10³ m²
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