a laser beam is aimed 15.95° above the horizontal at a mirror 11648m away .it glances off the mirror and continue for an additional 8570m at 11.40° above the horizon until it hits it's target .what is the resultant displacement of the beam to the target.
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12
Dear student
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11648 cos(15.95) = 11199.57
11648 sin(15.95)= 3200.85
(11199.57 i , 3200.85 j)
8570 cos(11.44) = 8399.73
8570 sin(11.44) = 1699.78
(8399.73 i , 1699.78 j)
R= (11199.57 + 8399.73)i + (3200.85+1699.78)j
R= (19599.3)i + (4900.63)j
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4
Answer:
The target of the laser beam is 20,200 m away with an angle elevation of 14.04°
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