Question

A laser signal sent towards the moon returns
after 'T' seconds. If 'C' is the speed of light then
the distance of the moon from the observer is​

Answer 1

Answer:

CT

Explanation:

distance = speed × time

=c × t = ct

Answer 2

Answer:

The moon's distance from the observer is​ $\frac{CT}{2}$.

Explanation:

From the question, we have that the laser takes "T" seconds to return and the speed of light is "C".

• We all know that distance(d) equals speed times time.

                            $d=CT$    (1)

This is the total distance traveled when traveling and returning, hence the moon's distance from the earth is,⇒$\frac{d}{2}$

So,

                                $\frac{d}{2}=\frac{CT}{2}$    (2)

Hence, the distance of the moon from the observer is​ $\frac{CT}{2}$.

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