A laser system is capable of lasing at several infrared wavelengths. If the most prominent wavelength is 3.1235 mm, then what would be the difference (in eV) between upper and lower levels for this wavelength?
Answers
Given info : A laser system is capable of lasing at several infrared wavelengths. If the most prominent wavelength is 3.1235 mm.
To find : the energy difference between the upper and lower level of this wavelength, is..
solution : wavelength, λ = 3.1235mm = 3.1235 × 10¯³ m
using formula, energy difference, ∆E = hc/λ
= (6.63 × 10¯³⁴ Js × 3 × 10^8 m/s)/(3.1235 × 10¯³)
= 6.63 × 3/3.1235 × 10¯²³ J
= 6.3678 × 10¯²³ J ≈ 6.4 × 10¯²³ J
we know, 1 eV = 1.6 × 10^-19 J
so, (6.4 × 10^-23)/(1.6 × 10^-19) J = 4 × 10¯⁴ eV
Therefore the energy difference between the upper level and the lower level is 4 × 10¯⁴ eV.
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Answer:
Explanation:
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