Question

A lawn is in the shape of a semicircle of diameter 35 dm. The lawn is surrounded by a flower bed of width 3.5 dm. Find the area of the flower bed in dm2

Answer 1

Answer:

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Answer 2

The area of flower bed is 423.5 sq.dm

Step-by-step explanation:

A lawn is in the shape of a semicircle

The lawn is surrounded by a flower bed of width 3.5 dm

Diameter of semicircle = 35 dm

Radius of semicircle r =$\frac{35}{2}=17.5 dm$

External Radius R = 17.5 +3.5 = 21 dm

Area of semicircle = $\frac{\pi r^2}{2}$

Area of flower bed = External area - Inner area = $\frac{\pi R^2}{2}-\frac{\pi r^2}{2} =\frac{22}{7}(21^2-17.5^2)=423.5 dm^2$

Hence The area of flower bed is 423.5 sq.dm

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