a lawn roller is 1m wide and 80 cm high. what area is covered in each revolution?
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surface area of cylinderical roller = 2πrh=2×227 ×40×100=25142.85 cm2
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[tex]width \: of \: roller \: 1m \\ dameter \: = 100cm \\ radius \: = 50 \: cm \\ circumference \: = 2 \times \frac{22}{7} \times 50 \\ = 2 \times 3.14 \times 50 \\ = 6.28 \times 50 \\ =31.40 \: cm \\ \: area \: covered \: in \: each \: revolution \: = circumference \times height \\ = 31.4 cm \times 80 cm
= 251.2 cm sq
= 251.2 cm sq
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