Question

A lawnmower takes 750 complete
revolutions to cut grass on a field
calculate the area of the field of the
diameter of the lawnmower is 84 can
and length is 1 m.​

Answer 1

Answer:

• The area of the road in 750 revolutions = 1980 m²

Given :

• Diameter of roller = 84

• Height of roller = 1 m

To find :

• The area of the road in 750 revolutions =?

Step-by-step explanation:

Diameter of roller = 84 [Given]

So, Radius => d/2 => 84/2 = 42 or 0.42 m

And height = 1 m [Given]

In one revolution, the road roller will cover an area equal to its lateral surface area.

Lateral Surface Area of cylinder = one revolution the area of the road covered = 2πrh

Substituting the values in the above formula, we get,

= 2 x 22/7 x 0.42 x 1

= 2.64

So, Area of the road in one revolution = 2.64 m²

Therefore, the area of the road in 750 revolutions = Area of the road in one revolution × 750

= 2.64 x 750

= 1980 m²

Thus, the area of the road in 750 revolutions = 1980 m²

Answer 2

GIVEN :

$\sf Radius \: of \: lawnmower = \frac{d}{2} = \frac{84}{2} = 42cm =0.42m \\ \\ \sf length \: of \: lawnmover = 1 \: m$

TO FIND :

$\\ \sf Area \: of \: the \: field$

SOLUTION :

• Lawnmower is in the shape of cylinder so we have to find lateral surface area of the lawnmower

$\boxed{ \bf \green{ L.S.A \: of \: lawnmover= 2\pi rh}}$

$\Longrightarrow \sf L.S.A = 2 \times \frac{22}{7} \times 0.42 \times 1 \\ \\ \Longrightarrow \sf L.S.A = 2.64 \: {m}^{2}$

• Lawnmower takes 750 revolution to cut grass of the field. So we multiply area of lawnmower by 750 to find area of field

Area of field = Area of lawnmover × 750

$\sf Area \: of \: field \: = 2.64 \times 750 \\ \\ \large \boxed{\sf \blue{ Area \: of \: field = 1980 \: {m}^{2} }}$