Math, asked by varunbodhi, 5 months ago

A lawnmower takes 750 complete revolutions to cut grass on a field. Calculate the area of the field if the diameter of the lawnmower is 84 cm and length is 1 m.
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Answers

Answered by Anonymous
17

\huge{\underline{\underline{\rm{\red{1980m²}}}}}

Given : Diameter of the roller = 84 cm

Length of the roller = 1 m

To find : The area of the road in 750 revolutions.

Explaination :

Diameter = 84 cm

Radius = 42 cm = 0.42 m

Height = 1 m

In one revolution, the road roller will cover an area equal to it's lateral surface area.

LSA of cylinder = One revolution of the area of the road covered = 2πrh

Substituting the values in the formula :

= 2 × 22/7 × 0.42 × 1

= 2.64

So, area of the road in one revolution = 2.64 m².

Therefore, the area of the road in 750 revolutions = Area of the road in one revolution × 750

= 2.64 × 750

= 1980 m²

Thus, the area of the road in 750 revolutions is 1980 m².

\huge{\rm{\red{Hope \:it \:helps\: you\:!}}}

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Answered by Anonymous
32

Given : Diameter of the roller = 84 cm

Length of the roller = 1 m

To find : The area of the road in 750 revolutions.

Explaination :

Diameter = 84 cm

Radius = 42 cm = 0.42 m

Height = 1 m

In one revolution, the road roller will cover an area equal to it's lateral surface area.

LSA of cylinder = One revolution of the area of the road covered = 2πrh

Substituting the values in the formula :

= 2 × 22/7 × 0.42 × 1

= 2.64

So, area of the road in one revolution = 2.64 m².

Therefore, the area of the road in 750 revolutions = Area of the road in one revolution × 750

= 2.64 × 750

= 1980 m²

Thus, the area of the road in 750 revolutions is 1980 m².

\huge{\underline{\underline{\rm{\red{1980m²}}}}}

\huge{\rm{\red{Hope \:it \:helps\: you\:!}}}

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