Question

a LCM of the given number 'x' and 'y' where y is a multiple of'x' is given by
(a) x
(b) y
(с) ху
(d) yx​

Answer 1

Answer:

Answer is option b)

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Answer 2

Given,

• y = multiple of x   [which means the HCF is x.]

$\sf{\implies HCF\times LCM=product \ of \ numbers}$

$\sf{\implies x \times LCM=x \times y}$

$\sf{\implies LCM=\dfrac{xy}{x}}$

bot x cancels off:

$\boxed{\sf{\implies LCM=y}}$

$\huge{\boxed{\bold{\sf{Answer:(b) \ y}}}}$