Question

a lead bullet of 100°c strikes a block of wood, gets embedded in it and melts. Find the speed of the bullet if 50℅ of the heat is shared by the bullet. specific heat of lead= 0.03 cal. latent heat of lead=5 cal/g and melting point of lead= 327 °c​

Answer 1

Explanation:

Heat energy utilised by lead bullet = Mc ∆ T + mL = Q

Equating Q and Q'

1/4 mv^2 = mc ∆ T + mL

1/4 v^2 = c ∆ T + L

Substituting value

C = 0.03

L = 5

∆ T = 327 - 100

= 227

V = 6.87 cm/s