Question

A lead bullet of specific heat 0.032 kcal kg-1C-1strikes a target with velocity of 300 ms-1.If the bullet is completely stopped by target ,find the rise in temperature of the bullet.Assume that the heat produced is equally shared by the target and the bullet.(J=4.2 J cal​-1).​

Answer 1

Here is ur Answer mate:-

Let m be the mass of the bullet.The kinetic energy associated with the bullet,

K.E=1/2mv^2

K.E=12×m×(300)2=m×45000J

According to law of conservation of energy:-

m×450002=m×4.2×103×0.032×θwhere, θ=rise in temperatureθ=450002×4.2×103×0.03=167.41

hope it helps you

Follow me pls