Physics, asked by ShantiJoshi, 5 months ago

A lead pellet of mass 4 g leaves an air gun with a velocity of 50 ms^(-1). What is the magnitude of potential energy stored by the spring of air gun?​

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Answered by rajutusharengineerin
0

Answer:

Explanation: Conservation of Energy ♦

→ The total energy of an Isolated System remains Constant  

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According to the Theory,  

→ Potential Energy of the Isolated System ( spring and the lead pellet ), was initially at its peak while the System was at rest. The transfer of Energy takes place spontaneously with all of P.E. transferring to K.E.  

=> P.E. ( Spring ) + K.E. ( Lead Pallet ) = 0

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Answered by yashsingh8704
0

Answer:

Explanation:

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