Question

A lead pencil consists of a cylinder of wood with a solid cylinder of graphite filled in the interior the diameter of the pencil is 7 mm and the diameter of the graphite is 1 mm if the length of the pencil is 14 cm, find the volume of the wood and that of the graphite​

Answer 1

Answer:

Volume of graphite

$\sf Radius \: of \: Graphite = r = \dfrac{Diameter \: of \: graphite}{2}= \dfrac{1}{2} mm$

$\displaystyle \: \frac{1}{2} \times \frac{1}{10} = \frac{1}{20} cm$

Height of graphite = h = 14 cm

$\sf \: volume \: of \: graphite \: cylinder \: = \pi {r}^{2} h$

$\displaystyle \sf\: ( \frac{22}{7} \times \frac{1}{20} \times \frac{1}{20} \times 14)m {m}^{3}$

$\displaystyle \sf \: (22 \times \frac{1}{1} \times \frac{1}{20} \times 2)$

$\displaystyle \sf \: = 0.11c {m}^{3}$

Volume of pencil

$Radius \: of \: pencil = \dfrac{ Diameter \: of \: pencil}{2} = \dfrac{1}{2}$

$\displaystyle= \frac{7}{20} cm$

$\displaystyle \: \frac{22}{7} \times \frac{7}{20} \times \frac{7}{20} \times 14)$

$\displaystyle \: 5.39c {m}^{ 3}$

Volume of wood = Volume of pencil - Volume of graphite.

$\sf \therefore \: volume \: of \: wood \: = 5.39 - 0.11 = 5.28c {m}^{3}$

Answer 2

Answer:

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