a lead shot of mass m is fired at a tree. the velocity of the bullet when entering and exiting the tree is 500ms-1 and 300ms-1 respectively. determine the temperature rise of the bullets by assuming that 50% of the lost energy is stored in the bullets.
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Explanation:
m
d
kM
Let V and v be the recoiling speed of the gun and velocity of the bullet respectively.
Conserving the momentum, we get
⇒mv−MV=0
⇒V=mv/M
Now conserving the energy, we get
⇒0.5×kd
2
=0.5×MV
2
⇒V
2
=kd
2
/M
⇒(mv/M)
2
=kd
2
/M
⇒v=
m
d
kM
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