Physics, asked by saijaltripathy2496, 5 hours ago

a lead shot of mass m is fired at a tree. the velocity of the bullet when entering and exiting the tree is 500ms-1 and 300ms-1 respectively. determine the temperature rise of the bullets by assuming that 50% of the lost energy is stored in the bullets.

Answers

Answered by debranjanMajumder
0

Explanation:

m

d

kM

Let V and v be the recoiling speed of the gun and velocity of the bullet respectively.

Conserving the momentum, we get

⇒mv−MV=0

⇒V=mv/M

Now conserving the energy, we get

⇒0.5×kd

2

=0.5×MV

2

⇒V

2

=kd

2

/M

⇒(mv/M)

2

=kd

2

/M

⇒v=

m

d

kM

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