Question

A lead storage battery has been used for one
month (30 days) at the rate of one hour per
day by drawing a constant current of
2 amperes. H.SO, consumed by the battery is
1) 1.12 mole 2) 2.24 mole
3) 3.36 mole
4) 4.48 mole​

Answer 1

Answer :

B

Solution :

The reactions occurring during discharge are:

Anode: Pb(s)+SO2−4(aq)→PbSO4(s)+2e−

At cathode:PbO2(s)+4H+(aq)+SO2−4(aq)+2e−→PbSO4(s)+2H2O(l)

Overall reaction reaction: Pb(s)+PbO2(s)+2H2SO4→2PbSO4(s)+2H2O(l)

Quantity of electricity consumed

=(2A)(30×3600s)=216000C

2×96500 coulombs consume H2SO4=2 moles

∴216000 coulombs will consume H2SO4

=196500×216000=2.24 moles.