A leader is 13m long . It is placed against a wall to reach a window.If its foot is 5 M away from the pole, how high is the window?
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1
Answer:
Step-by-step explanation:
According to Pythagoras theorem
Length of lader ^2 = (distance from foot )^2 + (height from window )^2
13^2 = 5^2 +h^2
169.= 25 +h^2
H^2 =169-25=144
H= √144
H=12meter
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Answered by
2
Ladder height, AB = 13 m
Distance of ladder from the foot, BC = 5 m
Using
( AB )² = ( BC )² + ( AC )²
( 13 )² = ( 5 )² + ( AC )²
169 = 25 + ( AC )²
AC² = 169 - 25 = 144
AC = √144
AC = √( 12 × 12 )
AC = √( 12² )
AC = 12 m
Hence,
Distance of ladder from the foot, BC = 5 m
Using
( AB )² = ( BC )² + ( AC )²
( 13 )² = ( 5 )² + ( AC )²
169 = 25 + ( AC )²
AC² = 169 - 25 = 144
AC = √144
AC = √( 12 × 12 )
AC = √( 12² )
AC = 12 m
Hence,
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