A leaser beam has intensity 2.5×10^(14) w/m^(2) . find the amplitude of electric and magnetic fields in the beam
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The energy crossing per unit area per unit time, perpendicular to the direction of propagation of EM wave is called intensity.
The relation between the intensity and the magnitude of electric field is,
I=12ε0E20C⇒E0=2I0ε0C−−−√=2×2.5×10148.85×10−12×3×108−−−−−−−−−−−−√=5×101826.55−−−−−√⇒E0=0.188×1018−−−−−−−−−−√⇒E0=0.43×109 Vm/
The relation between the intensity and the magnitude of magnetic field is,
I=12B20μ0C⇒B0=2I0μ0C−−−−√=2×2.5×1014×4×3.14×10−73×108−−−−−−−−−−−−−−−−√=62.8×1073×108−−−−−−√⇒B0=20.93×10−1−−−−−−−−−−√⇒E0=1.45 T
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The relation between the intensity and the magnitude of electric field is,
I=12ε0E20C⇒E0=2I0ε0C−−−√=2×2.5×10148.85×10−12×3×108−−−−−−−−−−−−√=5×101826.55−−−−−√⇒E0=0.188×1018−−−−−−−−−−√⇒E0=0.43×109 Vm/
The relation between the intensity and the magnitude of magnetic field is,
I=12B20μ0C⇒B0=2I0μ0C−−−−√=2×2.5×1014×4×3.14×10−73×108−−−−−−−−−−−−−−−−√=62.8×1073×108−−−−−−√⇒B0=20.93×10−1−−−−−−−−−−√⇒E0=1.45 T
Hope this information will clear your doubts about the topic.
If you have any more doubts just ask here on the forum and our experts will try to help you out as soon as possible.
Regards
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