Question

a least no. of 4 when increased by 5 is completely divisible by 12,15,20 and 35. the no. is .
a. 1275.
b.1265.
c.1235.
d.1255.​

Answer 1

Answer:

(d) 1255

1255 is correct answer

Explosion:

1255 + 5 = 1260

▪1260 = 12 × 105

▪1260 = 15 × 84

▪1260 = 20 × 63

▪1260 = 35 × 36

hope it helps you...✌

Answer 2

❖❖❖❖❖❖❖❖❖ QUESTION ❖❖❖❖❖❖❖❖❖❖❖

Least no. of 4 digits which when increased by 5 is completely divisible by 12,15,20 and 35. the no is__

OPTIONS

a) 1275

b) 1265

c) 1235

d) 1255

✤✤✤✤✤✤✤✤✤✤ ANSWER ✤✤✤✤✤✤✤✤✤✤✤

OPTION (D) 1255

➷➷➷➷➷➷➷➷EXPLANATION➷➷➷➷➷➷➷➷➷➷

Firstly find the LCM of 12, 15, 20 and 35

LCM(12, 15,20,35) = 420

LCM is 3 digit no. so multiplying it by 2

420×2 = 840

840 is also 3 digit so multiplying LCM by 3

420×3 = 1260

1260 is the least 4 digit no. divisible by 12,15,20 & 35

decreasing 1260 by 5

1260 - 5 = 1255

SO, 1255 IS THE LEAST 4 DIGIT NO. WHICH WHEN INCREASED BY 5 IS COMPLETELY DIVISIBLE BY 12,15,20 AND 35.

✿✿✿✿ I hope it will be helpful ✿✿✿✿