A leaves his school at the same time everyday. if he travels at 18 km/h he reaches at home 5:30.if he travels 8km/h he travels at 6:15. at what speed must he travels to arrive at home at 6:00
Answers
He must Travel at 9.82 km/Hr to arrive at home at 6:00 if He travels at 18 k/hr & reaches 5:30 and travels 8 km/hr & recahes at 6:15. Leaves school at same time
Step-by-step explanation:
Let say Distance between School & Home = 72D km
Time Taken at 18 km/hr Speed = 72D/18 = 4D hr
He left School = 5 : 30 - 4D
Time Taken at 8 km/hr Speed = 72D/8 = 9D hr
He left School = 6 : 15 - 9D
5 : 30 - 4D = 6 : 15 - 9D
=> 5D hrs = 45 mins
=> 5D = 45/60
=> D = 9/60
=> D = 3/20
4D hr = 4 * 9 /60 hr = 36 mins
He left School = 5 : 30 - 36 mins = 4 : 54
Time required to Reach at 6 :00 = 1 hr 6 min = 66 mins
= 66/60 hrs
= 11/10 hr
Distance = 72D = 72 * 3 /20 = 108/10 km
Speed = (108/10) /(11/10) = 108/11 km/hr
= 9.82 km/hr
He must Travel at 9.82 km/Hr to arrive at home at 6:00
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