Physics, asked by sada8270, 1 year ago

A led has a voltage drop of 2v across it and passes a current of 10ma

hyunxu: complete the question pls

Answers

Answered by prajapatiraj73p9np8s

0

R = V÷I

= 2 × 10^3 ÷10
= 2× 10^2
= 200 ohm

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