Math, asked by jiyamahanthy, 1 month ago

A lending library has a fixed charge for the first five days and an additional charge for each day thereafter. Ravi paid Rs 25 for a book he kept for ten days, while Reema paid Rs 21 for the book she kept for eight days. Find the fixed charge and the charge for each extra day

Answers

Answered by shervinsalaah
0

Answer: Rs 3 , Rs 2

Step-by-step explanation:

Let's assume

Fixed charge = x

Additional charge per day = y

Ravi

Additional days = Keeping days - Five days

                          = 10                     - 5

                          = 5

Additional charge = 5y

Fixed charge = x

Total charge = x + 5y = 25

Reema

Additional days = Keeping days - Five days

                          = 8                       - 5

                          = 3

Additional charge = 3y

Fixed charge = x

Total charge = x + 3y = 21

Now let's take the two equations separately

x + 5y = 25

x + 3y = 21

Let's subtract both because x is the only one which has similar coefficient so to eliminate x, we have to subtract

x + 5y -(x+3y) = 25 - 21

x + 5y -x -3y   =4

2y = 4

y = 4/2

y = 2

Substitute y=2 in first equation

x + 5y = 25

x + 10 = 25

x = 25 - 10

  =15

So, fixed charge per day = 15/5 = Rs 3

charge for each extra day = Rs 2

If my answer was helpful please mark me as brainliest:)

Answered by BrainlyArnab
0

Fixed charge = ₹5

Charge for each day extra = ₹2

Step-by-step explanation:

Let us consider,

  • fixed charge = x
  • charge of each extra = y

So,

  • Ravi kept book for ten days and paid 25

=> x + 10y = 25....(i)

  • Reema kept book for eight days and paid 21

=> x + 8y = 21....(ii)

Subtract (ii) from (i),

x + 10y = 25

- x ± 8y = ± 21

=> 2y = 4

=> y = 4/2

=> y = 2

Put the value of y in (i),

x + 10y = 25

=> x + 10(2) = 25

=> x + 20 = 25

=> x = 25 - 20

=> x = 5

So,

x = 5 & y = 2

Hence,

Fixed charge = 5

charge for each day extra = 2 per day

Hope it helps.

#BeBrainly :)

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