Question

A lending library has a fixed charge for the first three days and additional charge for each day thereafter. Saritha paid Rs 27 for a book kept for seven days, while Susy paid Rs 21 for the book she kept for five days. Find the fixed charge and the charge for each extra day

Answer 1

Answer:

Let the fixed charge for the first three days be Rs.x and extra charge for each day thereafter be Rs. y.

Then,

x+4y=27 .......(1)

x+2y=21 .......(2)

On subtracting equation 2 from equation 1, we get,

2y=6⟹y=3

Putting this value in equation 1, we get,

x=15

Therefore, the fixed charge is Rs.15 and the charge for each extra day is Rs.3.

Answer 2

Given : A lending library has a fixed charge for the first three days and an additional charge for each day thereafter. Saritha paid Rs 27 for a book kept for seven days, while Susy paid Rs 21 for the book she kept for five days.

 

Solution:

Elimination method is used to solve this Linear pair of Equations:

Let the fixed charge for the first three days be ₹ x and an additional charge for each day thereafter be ₹ y.

ATQ :

For Saritha :

x + 4y = 27 …………... (1)

For  Susy :  

x + 2y = 21 …………....(2)

On Subtracting equation (2)  from equation (1), we obtain :

x + 4y = 27

x + 2y = 21  

(-)  (-)     (-)

------------------

2y = 6

y = 6/2

y = 3  

Therefore , an additional charge for each day = ₹ 3  

On putting y = 3 in eq (1)  we obtain :  

x + 4y = 27  

x + 4(3) = 27  

x + 12 = 27

x = 27 - 12

x = 15

Therefore ,fixed charge = ₹ 3  

Hence, fixed charge is  ₹ 15 and an additional charge for each day is ₹ 3.

Hope this answer will help you…

 

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