Question

A lending library has a fixed charge for the first three days and an additional charge for each day thereafter Geeta oaid ₹27, for a book kept for seven days while mohit paid ₹21for the book he kept for 5 days find the fixed charges and the charge for each extra day​

Answer 1

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Question:-

A lending library has a fixed charge for the first three days and an additional charge for each day thereafter Geeta oaid ₹27, for a book kept for seven days while mohit paid ₹21for the book he kept for 5 days find the fixed charges and the charge for each extra day

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$\text{\large\underline{\orange{Solution:-}}}$

Let the fixed charge for 3 days$\bold{= x}$

and additional charge$\bold{= y}$

$\text{\large\underline{\pink{According\:to\:the\: Question:-}}}$

$\bold{⇒x+4y=27....eq1}$

$\bold{⇒x+2y=21....eq2}$

$\text{\large\underline{\green{Subtract eq1 and eq2}}}$

$\bold{⇒(3x+4y=27)−(3x+2y=21)}$$\bold{⇒2y=6⇒y=3}$

$\text{\large\underline{\pink{put y=3 in eq1}}}$

$\bold{⇒x+4×3=27}$

$\bold{⇒x=15}$

$\text{\large\underline{\red{Hence,}}}$

Fixed charges = Rs. 15

The charge for each extra day = Rs. 3

${\fbox{\boxed{\rm{\red{Answer:-Rs= 3}}}}}$

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Answer 2

Let the fixed charge for 3 days\bold{= x}=x

and additional charge\bold{= y}=y

\text{\large\underline{\pink{According\:to\:the\: Question:-}}}

AccordingtotheQuestion:-

\bold{⇒x+4y=27....eq1}⇒x+4y=27....eq1

\bold{⇒x+2y=21....eq2}⇒x+2y=21....eq2

\text{\large\underline{\green{Subtract eq1 and eq2}}}

Subtract eq1 and eq2

\bold{⇒(3x+4y=27)−(3x+2y=21)}⇒(3x+4y=27)−(3x+2y=21) \bold{⇒2y=6⇒y=3}⇒2y=6⇒y=3

\text{\large\underline{\pink{put y=3 in eq1}}}

put y=3 in eq1

\bold{⇒x+4×3=27}⇒x+4×3=27

\bold{⇒x=15}⇒x=15

\text{\large\underline{\red{Hence,}}}

Hence,

Fixed charges = Rs. 15

The charge for each extra day = Rs. 3