Physics, asked by katumbiangela48, 7 months ago

a length 550cm of a thin thread wraps around a cylinder exactly 25times calculate tje circumference and the radius of the cylinder (take pie to be twenty two over seven​

Answers

Answered by ExᴏᴛɪᴄExᴘʟᴏʀᴇƦ
9

\huge\sf\pink{Answer}

☞ Circumference = 22 cm

☞ Radius = 3.5 cm

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\huge\sf\blue{Given}

✭ Length of the thread is 550 cm

✭ Number of times wraps around a cylinder is 25

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\huge\sf\gray{To \:Find}

◈ The circumference and radius of the circle?

━━━━━━━━━━━━━

\huge\sf\purple{Steps}

So we know that if the thread wraps around the circle exactly 25 times,so then,

\underline{\boxed{\sf Length = Wraps \times Circumference}}

  • Wraps = 25
  • Length = 550

Substituting the given values,

\sf Length = Wraps \times Circumference

\sf Circumference = \dfrac{Length}{Wraps}

\sf Circumference = \dfrac{550}{25}

\sf \red{Circumference = 22 \ cm}

So now radius of the circle will be,

\underline{\boxed{\sf Circumference = 2\pi r}}

  • Circumference = 22 cm
  • π = ²²/7

Substituting the values,

\sf Circumference = 2\pi r

\sf 22 = 2\times \dfrac{22}{7} \times r

\sf 22\times \dfrac{7}{44} = r

\sf \dfrac{7}{2} = r

\sf \orange{Radius = 3.5 \ cm}

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Answered by Anonymous
18

Answer

☞ Circumference = 22 cm

☞ Radius = 3.5 cm

━━━━━━━━━━━━━

</p><p>\huge\sf\orange{Given}

✭ Length of the thread is 550 cm

✭ Number of times wraps around a cylinder is 25

━━━━━━━━━━━━━

\huge\sf\pink{To \:Find}

◈ The circumference and radius of the circle?

━━━━━━━━━━━━━

\huge\sf\purple{Steps}

So we know that if the thread wraps around the circle exactly 25 times,so then,

\underline {\boxed{\sf Length = Wraps \times Circumference}}

Length=Wraps×Circumference

  • Wraps = 25
  • Length = 550

Substituting the given values,

 \</p><p> Circumference \: Length=Wraps×Circumference</p><p>

➝ \sf Circumference = \dfrac{Length}{Wraps} \\ </p><p>

➝ \sf Circumference = \dfrac{550}{25}</p><p>	</p><p>

➝ \sf \green{Circumference = 22 \ cm}

So now radius of the circle will be,

\underline{\boxed{\sf Circumference = 2\pi r}} </p><p>

Circumference = 22 cm

π = ²²/7

Substituting the values,

➳ \sf Circumference = 2\pi r \\ </p><p></p><p>➳ \sf 22 = 2\times \dfrac{22}{7} \times r \\

➳ \sf 22\times \dfrac{7}{44} = r \\

➳ \sf \dfrac{7}{2} = r </p><p>

➳ \sf \blue{Radius = 3.5 \ cm}

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