Question

A length and breadth of a rectangular field are 58 metre 60 centimetre and 41 metre 40 centimeter respectively. how long will a man take to move four time round the field if he walks at the rate of 2.5 metres per second

Answer 1

$\sf{\huge{Heya \: mate.\: Solution\\below.}}$
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★ $<b><u><font color = "red">Answer - ↓</font color></u></b>$ ★




♠ First we will find the total distance to be covered, i.e. the perimeter.


Given length (l) = 58 m 60 cm = 58.6 m

Given breadth (b) = 41 m 40 cm = 41.4 m



•°• Perimeter,

$\sf{= 2 (l + b)}$

$\sf{= 2 (58.6 + 41.4)}$

$\sf{= 2 \times 100}$

$\sf{= 200 m}$



♦ And, the man will go four times around the field.


•°• Total distance,

$\sf{= 200 \times 4}$

$\sf{= 800 m}$





♠ Then,

Total distance = 800 m

Speed = 2.5 m/s



•°• Time,

$\sf{= \frac{Total Distance}{Speed}}$

$\sf{= \frac{800}{2.5}}$

$\sf{= 320 s}$

$\sf{≈ 5.3 min}$





♥ •°• The man will take about 5 min and 3 seconds to go around the field four times. ♥
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Thank you... (^_-)

Answer 2

Answer:

Perimeter of field=2*(5860+4140)

=20000 m

4 times perimeter=20000*4=80000 m

time taken by man=80000/2.5

=32000secs