A length of 150 cm of a potentiometer wire is required to balance the emf of a cell. When a 5 resistor is connected across the terminals of the cell, the length required for balance is 125 cm. The internal resistance of the cell is
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Length of the potentiometer wirel
1
=150cm
Resistance R=5Ω
balancing length is obtained at l
2
=125cm
Internal resistance r=?
we have,
r=R[
l
2
l
1
−1]
=5[
125
150
−1]
=5[
125
25
]
=1Ω
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