Question

A length of a bacteria enlarged 50000 times attains a length of 5cm.what is the actual length of the bacteria if the length is enlarged 20000 times only what would be it's enlarged length

Answer 1

Let the -

• length of bacteria be x cm.

According to question,

Length of a bacteria enlarged 50000 times and attains a length of 5 cm.

Enlarged length of bacteria × Assumed the length of bacteria (actual length) = Attained length of the bacteria

$\implies$ $\sf{50000 \:\times\:x \:= \:5}$

$\implies$ $\sf{x \:=\:\dfrac{ 5}{50000}}$

$\implies$ $\sf{x\: = \:\dfrac{1}{10000}}$ cm

•°• Actual length of bacteria is 1/10000 cm.

Also,

If the length of bacteria is enlarged 20000 times, then we have to find the enlarged length of bacteria.

If bacteria enlarged 50000 times then it attains a length of 5 cm.

Now, If bacteria enlarged 20000 times then it attains a length of y cm.

$\implies$ $\sf{\dfrac{50000}{5}\:=\:\dfrac{20000}{y}}$

$\implies$ $\sf{\dfrac{10000}{1}\:=\:\dfrac{20000}{y}}$

Cross-multiply them

$\implies$ $\sf{10000y\: =\: 20000}$

$\implies$ $\sf{y\:=\:\dfrac{20000}{10000}}$

$\implies$ $\sf{y\:=\:2}$ cm

•°• If bacteria enlarged 20000 times, then it attains a length of 2 cm.

Answer 2

Answer:

Step-by-step explanation:

$\bf\underline{Given:-}$

Length of bacteria is 5 cm if its photograph is enlarged 50,000 times.

$\bf\underline{To \ Find:-}$

Its enlarged length.

$\bf\underline{Solution:-}$

$\sf{Let's \: Assume \: the \: original \: length \: of \: bacteria \: be \: x \: cm}$

$\sf According \: to \: the \: Question$

$\sf\implies 50,000 \times x = 5 \: cm$

$\sf\implies x = \frac{5}{50,0000}$

$\bf\implies x = 1 \: micrometer$

$\sf Let \: the \: enlarged \: size \: of \: the \: bacteria \: after \: 20,000 \: times \: enlargementv = y \: cm$

$\sf\implies 20,000\times\frac{1}{10000}=y$

$\sf\implies y=\frac{20000}{10000}$

$\bf\implies y =2 \: cm$

$\bold{Hence, \: the \: enlarged \: image \: of \: bacteria \: after \: 20,000 \: magnification \: is \: 2 \: cm.}$