a length of a cylinderical conducting wire is doubled and area of cross section is half , then resistance of the wire becomes
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Hence Resistance will become 4 times in the new condition, if the area is doubled and length is halved.
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a length of a cylinderical conducting wire is doubled and area of cross section is half , then resistance of the wire become
solution
R′=ρA2L. So, R = 2R'. Hence, If the length of a wire is doubled, then its resistance becomes 2 times
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