Question

(a) length of a rectangle, if its perimeter = 32 cm and width = 5 cm
1
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Answer 1

perimeter of rectangle = 2(l+b)

32=2(l+5)

32/2= (l+5)

16=(l+5)

16-5=l

11=l

So length is 11 cm

hope it helps...

Answer 2

given perimeter=32

width(b)=5 cm

2(l+b)=32

2(l+5)=32

2l+10=32

2l=32-10

2l=22

l=11

Therefore,length of the rectangle is 11 cm