Question

a length of a rectangle is 10 cm more than its width its area is 119 CM square find the Length and width of the rectangle

Answer 1

let width be x
therefore l=x+10
area=l×b
=(x+10)×x
${x}^{2} + 10x - 119 = 0 \\ {x}^{2} - 7x + 17x + - 119 = 0$
x(x-7)+17(x-7)
(x+17)(x-7)
therefore x=7 as -17 is not possible

Answer 2

.Solution.

let width= xcm

=> x (x+10)= 119cm^2

=> x^2+10x - 119=0

=> D= b^2 - 4ac

= 100+476

= 576

roots= -b ±√D/2a

= -10 ± 24/2

= -34/2 or 34/2

so,length will not be negative..
so, x= 17

hence , width= 17cm

& length = 17+10=27cm

__________

hope it helps☺✌✌