Question

a length of a rectangle is 2 cm more than its width and its perimeter is 14cm,then the area of rectangle is​

Answer 1

Step-by-step explanation:

the length of an rectangle =2cm

the width is 2cm more=2x

the perimeter of triangle=14cm

the area of an rectangle =L×B

=2×2X

=4X

X=4

THEREFORE X = 4

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Answer 2

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Given :-

• A length of a rectangle is 2 cm more than its width
• Perimeter is 14cm

To find :-

• Area of the rectangle.

Solution :-

Let the width of the rectangle be x cm

As per the first condition :-

• Length of a rectangle is 2 cm more than its width

Length = x + 2 cm

We know that the perimeter of the rectangle is calculated using the formula :-

$\bf{\large{\underline{\boxed{\rm{\purple{Perimeter\:of\:a\:rectangle \:=\:2\:(l\:+\:b\:}}}}}}$

Plug in the values in the above formula,

14 = 2 ( x + 2 + x)

14 = 2x + 4 + 2x

14 = 2x + 2x + 4

14 = 4x + 4

14 - 4 = 4x

10 = 4x

$\large\frac{10}{4}$ = x

2.5 = x

Value of x = width = 2.5 cm

Length = x + 2 = 2.5 + 2 = 4.5 cm

We now have the length and width of the rectangle and we can easily calculate the area of the rectangle using the formula.

$\bf{\large{\underline{\boxed{\rm{\blue{Area\:of\:a\:rectangle \:=\:Length \times\:breadth}}}}}}$

Plug in the values,

Area = 4.5 × 2.5

Area = 11.25

•°• Area of the rectangle = 11.25 sq.cm