a length of a spanner 10cm used to tighten a nut with a force of 20 N. Find the value of torque
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Solution:
\bot⊥ distance = 10 cm = 1/10 m
Force applied = 5N
Moment of force = F\times× \bot⊥ distance
= 51/10 m = 0.5 Nm
Explanation:
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